(C) To convert a galvanometer into a voltmeter,a high resistance $R$ must be connected in series with the galvanometer.Given: Galvanometer resistance

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(C) To convert a galvanometer into a voltmeter,a high resistance $R$ must be connected in series with the galvanometer.Given: Galvanometer resistance $G = 25 \,\Omega$,full-scale deflection current $i_g = 6 \,mA = 6 \times 10^{-3} \,A$,and maximum voltage to be measured $V = 6 \,V$.The formula for the series resistance $R$ is given by $R = \frac{V}{i_g} - G$.Substituting the values: $R = \frac{6}{6 \times 10^{-3}} - 25$.$R = 1000 - 25 = 975 \,\Omega$.Thus,a resistance of $975 \,\Omega$ must be connected in series.

Class 12 Physics Moving Charges and Magnetism The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

Medium

$A$ galvanometer of $25 \,\Omega$ resistance can read a maximum current of $6 \,mA$. It can be used as a voltmeter to measure a maximum of $6 \,V$ by connecting a resistance to the galvanometer. Identify the correct choice in the given answers.

A
$1025 \,\Omega$ in series
B
$1025 \,\Omega$ in parallel
C
$975 \,\Omega$ in series
D
$975 \,\Omega$ in parallel

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Moving Charges and Magnetism

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The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

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$A$ millivoltmeter of $25 \, mV$ range is to be converted into an ammeter of $25 \, A$ range. The value (in $\Omega$) of the necessary shunt will be:

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An ammeter reads up to $1\, A$. Its internal resistance is $0.81\, \Omega$. To increase the range to $10\, A$,the value of the required shunt is ............ $\Omega$.

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$A$ galvanometer of $25 \,\Omega$ resistance can read a maximum current of $6 \,mA$. It can be used as a voltmeter to measure a maximum of $6 \,V$ by connecting a resistance to the galvanometer. Identify the correct choice in the given answers.

Similar Questions

Consider a galvanometer shunted with $5\, \Omega$ resistance and $2\, \%$ of the total current passes through it. What is the resistance of the given galvanometer? (In $\Omega$)

An ammeter of $100 \, \Omega$ resistance gives full-scale deflection for a current of $10^{-5} \, A$. The shunt resistance required to convert it into an ammeter of $1 \, A$ range will be:

$A$ millivoltmeter of $25 \, mV$ range is to be converted into an ammeter of $25 \, A$ range. The value (in $\Omega$) of the necessary shunt will be:

If the number of turns in the coil of a galvanometer is decreased,then the resistance of the galvanometer:

An ammeter reads up to $1\, A$. Its internal resistance is $0.81\, \Omega$. To increase the range to $10\, A$,the value of the required shunt is ............ $\Omega$.

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