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(B) For a Galileo telescope,the magnifying power $m$ is given by the formula $m = \frac{f_o}{f_e}$,where $f_o$ is the focal length of the objective an

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$98$

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(B) For a Galileo telescope,the magnifying power $m$ is given by the formula $m = \frac{f_o}{f_e}$,where $f_o$ is the focal length of the objective and $f_e$ is the focal length of the eyepiece.Given $f_o = 100\,cm$ and $m = 50$,we can calculate the focal length of the eyepiece as:$f_e = \frac{f_o}{m} = \frac{100}{50} = 2\,cm$.In normal adjustment,the distance $L$ between the objective and the eyepiece for a Galileo telescope is given by $L = f_o - f_e$.Substituting the values,we get $L = 100\,cm - 2\,cm = 98\,cm$.

$A$ Galileo telescope has an objective of focal length $100\,cm$ and magnifying power $50$. The distance between the two lenses in normal adjustment will be......$cm$

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