A disc having velocity v_0 and angular speed | vedclass

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(D) $1$. The velocity of the point of contact of the disc with the plank is $v_{contact} = v_0 + \omega_0 R$ in the forward direction. Since the plank

Vedclass · Accepted Answer

Angular momentum of the disc about any point on the horizontal surface remains conserved.

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(D) $1$. The velocity of the point of contact of the disc with the plank is $v_{contact} = v_0 + \omega_0 R$ in the forward direction. Since the plank is initially at rest,there is relative motion,and kinetic friction acts on the disc in the backward direction.$2$. The friction force on the disc is backward,and the reaction force on the plank is forward. Since the external force on the system (disc + plank) in the horizontal direction is zero,the total linear momentum of the system is conserved.$3$. The friction force is kinetic because there is relative slipping between the disc and the plank until pure rolling starts.$4$. The angular momentum of the disc about a point on the horizontal surface is not conserved because the friction force exerts a torque about any point on the horizontal surface (except the point of contact itself,but the question specifies 'any point'). Therefore,option $D$ is incorrect.

$A$ disc having velocity $v_0$ and angular speed $\omega_0$ in the anticlockwise direction is placed on a rough plank. Initially,the plank is at rest. (Assume the length of the plank is very large). Choose the $INCORRECT$ option.

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