A disaccharide X cannot be oxidised by bromin | vedclass

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(A) disaccharide that cannot be oxidized by bromine water is a non-reducing sugar,meaning it lacks a free hemiacetal or hemiketal group. Sucrose is a

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(A) disaccharide that cannot be oxidized by bromine water is a non-reducing sugar,meaning it lacks a free hemiacetal or hemiketal group. Sucrose is a non-reducing sugar because its glycosidic linkage involves both anomeric carbons ($C1$ of glucose and $C2$ of fructose).Upon acid hydrolysis,sucrose yields $D-(+)$-glucose and $D-(-)$-fructose. The resulting mixture is laevorotatory because the specific rotation of $D-(-)$-fructose $(-92^{\circ})$ is greater in magnitude than that of $D-(+)$-glucose $(+52.5^{\circ})$.Structure $A$ represents sucrose,which consists of $\alpha-D$-glucopyranose and $\beta-D$-fructofuranose units linked by an $\alpha, \beta-1,2$-glycosidic bond.

$A$ disaccharide $X$ cannot be oxidised by bromine water. The acid hydrolysis of $X$ leads to a laevorotatory solution. The disaccharide $X$ is

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