A dice is thrown twice. The probability of getting $4, 5$ or $6$ in the first throw and $1, 2, 3$ or $4$ in the second throw is
$1$
$\frac{1}{3}$
$\frac{7}{{36}}$
None of these
A die is thrown, find the probability of following events: A number more than $6$ will appear,
If any four numbers are selected and they are multiplied, then the probability that the last digit will be $1, 3, 5$ or $7$ is
Two dice are thrown together. The probability that at least one will show its digit $6$ is
The probability of choosing at random a number that is divisible by $6$ or $8$ from among $1$ to $90$ is equal to
A number is chosen from first $100$ natural numbers. The probability that the number is even or divisible by $5$, is