A cylinder is closed at both ends by hemisphe | vedclass

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(C) The article consists of a cylinder and two hemispheres at its ends.Given: Radius $r = 21 \, cm$,Total height $H = 92 \, cm$.The height of the cyli

Vedclass · Accepted Answer

$12144$

Vedclass · Answer

(C) The article consists of a cylinder and two hemispheres at its ends.Given: Radius $r = 21 \, cm$,Total height $H = 92 \, cm$.The height of the cylindrical part $h = H - 2r = 92 - 2(21) = 92 - 42 = 50 \, cm$.The total surface area of the article = (Curved surface area of cylinder) + $2$ $	imes$ (Curved surface area of hemisphere).Total surface area = $2\pi rh + 2(2\pi r^2) = 2\pi r(h + 2r)$.Substituting the values: $2 	imes \frac{22}{7} 	imes 21 	imes (50 + 2(21)) = 2 	imes 22 	imes 3 	imes (50 + 42) = 132 	imes 92 = 12,144 \, cm^2$.

$A$ cylinder is closed at both ends by hemispheres. The radius of the cylinder is $21 \, cm$ and the total height of the article is $92 \, cm$. Find the total surface area of the article (in $cm^2$).

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