A cyclist driving at $5\, m s ^{-1}$ picks a velocity of $10\, m s ^{-1}$ over a distance of $50\, m$. Calculate $(i)$ acceleration $(ii)$ time in which the cyclist picks up the above velocity.
A cyclist driving at $5\, m s ^{-1}$ picks a velocity of $10\, m s ^{-1}$ over a distance of $50\, m$. Calculate $(i)$ acceleration $(ii)$ time in which the cyclist picks up the above velocity.
Given $u=5 m s ^{-1}, v=10 m s ^{-1}, S =50 m , a=?$
$t=?$
Applying $v^{2}-u^{2}=2 a S$
$(10)^{2}-(5)^{2}=2 \times a \times 50$
$75=100 a$
$a=0.75 m s ^{-2}$
$v=u+a t$
$10=5+0.75 \times t$
Therefore, $t=\frac{5}{0.75}=6.67 s$
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