A current carrying coil is placed with its axis perpendicular to $N-S$ direction. Let horizontal component of earth's magnetic field be $H_0$ and magnetic field inside the loop be $H$. If a magnet is suspended inside the loop, it makes angle $\theta $ with $H$. Then $\theta =$
A current carrying coil is placed with its axis perpendicular to $N-S$ direction. Let horizontal component of earth's magnetic field be $H_0$ and magnetic field inside the loop be $H$. If a magnet is suspended inside the loop, it makes angle $\theta $ with $H$. Then $\theta =$
- A
${\tan ^{ - 1}}\,\left( {\frac{{{H_0}}}{H}} \right)$
- B
${\tan ^{ - 1}}\,\left( {\frac{H}{{{H_0}}}} \right)$
- C
$\cos e{c^{ - 1}}\,\left( {\frac{H}{{{H_0}}}} \right)$
- D
${\cot ^{ - 1}}\,\left( {\frac{{{H_0}}}{H}} \right)$
Similar Questions
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- [AIIMS 1999]
A magnetic compass needle oscillates $30$ times per minute at a place where the dip is $45^o$, and $40$ times per minute where the dip is $30^o$. If $B_1$ and $B_2$ are respectively the total magnetic field due to the earth at the two places, then the ratio $B_1/B_2$ is best given by
A magnetic compass needle oscillates $30$ times per minute at a place where the dip is $45^o$, and $40$ times per minute where the dip is $30^o$. If $B_1$ and $B_2$ are respectively the total magnetic field due to the earth at the two places, then the ratio $B_1/B_2$ is best given by
- [JEE MAIN 2019]