$A$ copper wire of length $4.0 \, m$ and area of cross-section $1.2 \, cm^2$ is stretched with a force of $4.8 \times 10^3 \, N$. If Young's modulus for copper is $1.2 \times 10^{11} \, N/m^2$,the increase in the length of the wire will be:

  • A
    $1.33 \, mm$
  • B
    $1.33 \, cm$
  • C
    $2.66 \, mm$
  • D
    $2.66 \, cm$

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