$A$ copper rod of length $l$ is rotated about one end perpendicular to the magnetic field $B$ with constant angular velocity $\omega$. The induced e.m.f. between the two ends is

  • A
    $\frac{1}{2}B\omega l^2$
  • B
    $\frac{3}{4}B\omega l^2$
  • C
    $B\omega l^2$
  • D
    $2B\omega l^2$

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