$A$ convex mirror of radius of curvature $30 \,cm$ forms an image that is half the size of the object. The object distance is: (in $\,cm$)

An object is placed at $10 \text{ cm}$ in front of a concave mirror of focal length $15 \text{ cm}$. The image formed will be . . . . . . .

An object is placed at a distance of $f$ from the pole of a convex mirror of focal length $f$. Where will the image be formed?

The distance of an object from a spherical mirror is equal to the focal length of the mirror. Then the image:

$A$ virtual image three times the size of the object is obtained with a concave mirror of radius of curvature $36 \ cm$. The distance of the object from the mirror is ........ $cm$.

An object is gradually moving away from the focal point of a concave mirror along the axis of the mirror. The graphical representation of the magnitude of linear magnification $(m)$ versus distance of the object from the mirror $(x)$ is correctly given by
(Graphs are drawn schematically and are not to scale)