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(B) For a conducting sphere of radius $R$ carrying a charge $Q$,the charge resides entirely on its outer surface.Inside the conductor,the electric fie

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$\frac{Q}{4\pi \epsilon_0 R}$ and Zero

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(B) For a conducting sphere of radius $R$ carrying a charge $Q$,the charge resides entirely on its outer surface.Inside the conductor,the electric field $E$ is zero everywhere because the charges are in electrostatic equilibrium.However,the electric potential $V$ inside the conductor is constant and equal to the potential at its surface.The potential at the surface is given by $V = \frac{Q}{4\pi \epsilon_0 R}$.Therefore,at the centre of the sphere,the electric potential is $\frac{Q}{4\pi \epsilon_0 R}$ and the electric field is $0$.

$A$ conducting sphere of radius $R$ is given a charge $Q$. The electric potential and the electric field at the centre of the sphere respectively are

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