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(C) The magnetic force on a small current element $d\overrightarrow{l}$ in a magnetic field $\overrightarrow{B}$ is given by $d\overrightarrow{F} = i(

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Zero

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(C) The magnetic force on a small current element $d\overrightarrow{l}$ in a magnetic field $\overrightarrow{B}$ is given by $d\overrightarrow{F} = i(d\overrightarrow{l} 	imes \overrightarrow{B})$.For a closed loop,the net magnetic force is $\overrightarrow{F} = \oint i(d\overrightarrow{l} 	imes \overrightarrow{B})$.Since the magnetic field $\overrightarrow{B}$ is uniform,it can be taken out of the integral: $\overrightarrow{F} = i(\oint d\overrightarrow{l}) 	imes \overrightarrow{B}$.For any closed loop,the vector sum of all infinitesimal length elements $\oint d\overrightarrow{l}$ is zero.Therefore,the net magnetic force $\overrightarrow{F} = i(0) 	imes \overrightarrow{B} = 0$.

$A$ conducting circular loop of radius $r$ carries a constant current $i$. It is placed in a uniform magnetic field $\overrightarrow{B}$,such that $\overrightarrow{B}$ is perpendicular to the plane of the loop. The magnetic force acting on the loop is

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