(D) The capacitance of a parallel plate capacitor is given by $C = \frac{\epsilon_0 A}{d}$.The potential difference between the plates is $V = Ed$.The

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$\frac{1}{2} \epsilon_0 E^2 Ad$

(D) The capacitance of a parallel plate capacitor is given by $C = \frac{\epsilon_0 A}{d}$.The potential difference between the plates is $V = Ed$.The energy stored in the capacitor is $U = \frac{1}{2} C V^2$.Substituting the values of $C$ and $V$:$U = \frac{1}{2} \left( \frac{\epsilon_0 A}{d} \right) (Ed)^2$.$U = \frac{1}{2} \left( \frac{\epsilon_0 A}{d} \right) E^2 d^2$.$U = \frac{1}{2} \epsilon_0 E^2 Ad$.

Class 12 Physics Electric Potential and Capacitance Energy Stored in a Capacitor

Medium

$A$ parallel plate capacitor has a uniform electric field $E \ (V/m)$ in the space between the plates. If the distance between the plates is $d \ (m)$ and the area of each plate is $A \ (m^2)$,then the energy (joules) stored in the capacitor is:

A
$E^2 Ad / \epsilon_0$
B
$\frac{1}{2} \epsilon_0 E^2$
C
$\epsilon_0 EAd$
D
$\frac{1}{2} \epsilon_0 E^2 Ad$

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Electric Potential and Capacitance

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Energy Stored in a Capacitor

$A$ capacitor of capacity $C$ has charge $Q$ and stored energy is $W$. If the charge is increased to $2Q$,the stored energy will be

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$A$ parallel plate capacitor has a uniform electric field $E$ in the space between the plates. If the distance between the plates is $d$ and the area of each plate is $A,$ the energy stored in the capacitor is

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$A$ variable condenser is permanently connected to a $100 \ V$ battery. If the capacity is changed from $2 \ \mu F$ to $10 \ \mu F$,then the change in energy is equal to:

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$A$ parallel plate capacitor has a uniform electric field $E \ (V/m)$ in the space between the plates. If the distance between the plates is $d \ (m)$ and the area of each plate is $A \ (m^2)$,then the energy (joules) stored in the capacitor is:

Similar Questions

$A$ capacitor of capacity $C$ has charge $Q$ and stored energy is $W$. If the charge is increased to $2Q$,the stored energy will be

Two capacitors,each of value $10 \ \mu F$,are connected in parallel and charged to $200 \ V \ DC$. What is the energy stored in the combination in Joules?

$A$ parallel plate capacitor has a uniform electric field $E$ in the space between the plates. If the distance between the plates is $d$ and the area of each plate is $A,$ the energy stored in the capacitor is

If the charge on the capacitor is increased by $2 \text{ C}$, the energy stored in it increases by $21 \%$. The original charge on the capacitor is (in $\text{ C}$)

$A$ variable condenser is permanently connected to a $100 \ V$ battery. If the capacity is changed from $2 \ \mu F$ to $10 \ \mu F$,then the change in energy is equal to:

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