A compound contains x,y,and z atoms. The oxid | vedclass

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Question

(B) For a neutral compound,the sum of the oxidation numbers of all atoms must be equal to $0$. Checking the options: $(1)$ $xyz$: $(+3) + (-5) + (+1)

Vedclass · Accepted Answer

$xyz_2$

Vedclass · Answer

(B) For a neutral compound,the sum of the oxidation numbers of all atoms must be equal to $0$. Checking the options: $(1)$ $xyz$: $(+3) + (-5) + (+1) = -1 
eq 0$ $(2)$ $xyz_2$: $(+3) + (-5) + 2 	imes (+1) = +3 - 5 + 2 = 0$ $(3)$ $x_2yz$: $2 	imes (+3) + (-5) + (+1) = +6 - 5 + 1 = +2 
eq 0$ $(4)$ $(xy)_2z$: $2 	imes ((+3) + (-5)) + (+1) = 2 	imes (-2) + 1 = -3 
eq 0$ Therefore,the correct formula is $xyz_2$.

$A$ compound contains $x$,$y$,and $z$ atoms. The oxidation number of $x$ is $+3$,$y$ is $-5$,and $z$ is $+1$. The possible formula of the compound is:

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