$1 \ mol$ of compound $N_2H_4$ loses $10 \ mol$ of electrons to form a new compound $Y$. Assuming all nitrogen atoms are present in compound $Y$,what is the oxidation state of $N$ in compound $Y$?
- A$-1$
- B$-3$
- C$+3$
- D$+5$
Explore More
Similar Questions
In alkaline condition,$KMnO_4$ reacts as follows:
$2KMnO_4 + 2KOH \to 2K_2MnO_4 + H_2O + O$
The equivalent weight of $KMnO_4$ is:
$2KMnO_4 + 2KOH \to 2K_2MnO_4 + H_2O + O$
The equivalent weight of $KMnO_4$ is:
Medium
View SolutionIn which of the following compounds does chlorine have the highest oxidation state?
The oxidation number of $N$ in $N_3H$ is ..........
Medium
View SolutionIf $HNO_3$ changes into $N_2O$,the oxidation number of nitrogen is changed by
Medium
View SolutionWhat is the oxidation number of $Cl$ in $CaOCl_2$?
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo