A composite slab consisting of different medi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The shift produced by a slab of thickness $t$ and refractive index $\mu_{slab}$ in a surrounding medium of refractive index $\mu_{surrounding}$ is

Vedclass · Accepted Answer

On the object

Vedclass · Answer

(A) The shift produced by a slab of thickness $t$ and refractive index $\mu_{slab}$ in a surrounding medium of refractive index $\mu_{surrounding}$ is given by $\Delta x = t(1 - \frac{\mu_{surrounding}}{\mu_{slab}})$.The total shift produced by the three slabs is:$\Delta x_{total} = 45(1 - \frac{4/3}{1.5}) + 24(1 - \frac{4/3}{1}) + 54(1 - \frac{4/3}{1.5})$$= 45(1 - \frac{4/3}{3/2}) + 24(1 - 4/3) + 54(1 - \frac{4/3}{3/2})$$= 45(1 - 8/9) + 24(-1/3) + 54(1 - 8/9)$$= 45(1/9) - 8 + 54(1/9)$$= 5 - 8 + 6 = 3 \, cm$.The real distance of the object from the mirror is $d_{real} = 20 + 45 + 24 + 54 + 10 = 153 \, cm$.The apparent distance of the object from the mirror is $d_{apparent} = d_{real} - \Delta x_{total} = 153 - 3 = 150 \, cm$.Since the apparent distance is equal to the radius of curvature $(R = 150 \, cm)$,the object appears to be at the center of curvature. Therefore,the final image is formed at the object itself.

Similar Questions

The observer at $O$ views two closely spaced spots on a vertical wall through an angled glass slab as shown. As seen by the observer,the spots appear

$A$ plane glass slab is kept over a coloured word '$VIBGYOR$',where the colour of each letter corresponds to the colours in white light. The letter which appears least raised is

$A$ glass slab of thickness $4 \ cm$ contains the same number of waves as $5 \ cm$ of water when both are traversed by the same monochromatic ray of light. The refractive index of water is $4/3$. What is the refractive index of glass?

Vedclass Test Series

Exam Paper Generator

Online Exam Module