$A$ company selected $4000$ households at random and surveyed them to find out a relationship between income level and the number of television sets in a home. The information so obtained is listed in the following table:
Monthly income (in Rs) $0$ Televisions $1$ Television $2$ Televisions Above $2$ Televisions $< 10000$ $20$ $80$ $10$ $0$ $10000-14999$ $10$ $240$ $60$ $0$ $15000-19999$ $0$ $380$ $120$ $30$ $20000-24999$ $0$ $520$ $370$ $80$ $25000$ and above $0$ $1100$ $760$ $220$
Find the probability of a household earning $Rs. 25000$ and more per month and owning $2$ televisions.
| Monthly income (in Rs) | $0$ Televisions | $1$ Television | $2$ Televisions | Above $2$ Televisions |
| $< 10000$ | $20$ | $80$ | $10$ | $0$ |
| $10000-14999$ | $10$ | $240$ | $60$ | $0$ |
| $15000-19999$ | $0$ | $380$ | $120$ | $30$ |
| $20000-24999$ | $0$ | $520$ | $370$ | $80$ |
| $25000$ and above | $0$ | $1100$ | $760$ | $220$ |
Find the probability of a household earning $Rs. 25000$ and more per month and owning $2$ televisions.
- A$0.109$
- B$0.19$
- C$0.99$
- D$0.59$
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Over the past $200$ working days,the number of defective parts produced by a machine is given in the following table:
Number of defective parts $0$ $1$ $2$ $3$ $4$ $5$ $6$ $7$ $8$ $9$ $10$ $11$ $12$ $13$ Days $50$ $32$ $22$ $18$ $12$ $12$ $10$ $10$ $10$ $8$ $6$ $6$ $2$ $2$
Determine the probability that tomorrow's output will have at least one defective part.
| Number of defective parts | $0$ | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ | $7$ | $8$ | $9$ | $10$ | $11$ | $12$ | $13$ |
| Days | $50$ | $32$ | $22$ | $18$ | $12$ | $12$ | $10$ | $10$ | $10$ | $8$ | $6$ | $6$ | $2$ | $2$ |
Determine the probability that tomorrow's output will have at least one defective part.
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Outcome $1$ $2$ $3$ $4$ $5$ $6$ Frequency $180$ $150$ $160$ $170$ $150$ $190$
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