A coin is based so that a head is twice as li | vedclass

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Question

Let probability of tail is $\frac{1}{3}$

$\Rightarrow$ Probability of getting head $=\frac{2}{3}$

$	herefore$ Probability of getting $2$ tails

Vedclass · Accepted Answer

$\frac{2}{9}$

Vedclass · Answer

Let probability of tail is $\frac{1}{3}$

$\Rightarrow$ Probability of getting head $=\frac{2}{3}$

$	herefore$ Probability of getting $2$ tails and $1$ head

$=\left(\frac{1}{3} 	imes \frac{2}{3} 	imes \frac{1}{3}ight) 	imes 3$

$=\frac{2}{27} 	imes 3$

$=\frac{2}{9}$

A coin is based so that a head is twice as likely to occur as a tail. If the coin is tossed $3$ times, then the probability of getting two tails and one head is-

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