A coil,a capacitor,and an AC source of rms vo | vedclass

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(C) In an $LCR$ series circuit,the maximum current occurs at resonance,where the impedance $Z$ is equal to the resistance $R$ of the coil.Given $V_{rm

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$1.5$

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(C) In an $LCR$ series circuit,the maximum current occurs at resonance,where the impedance $Z$ is equal to the resistance $R$ of the coil.Given $V_{rms} = 24 \,V$ and $I_{rms, max} = 6 \,A$.At resonance,$Z = R = V_{rms} / I_{rms, max} = 24 / 6 = 4 \,\Omega$.This $R = 4 \,\Omega$ is the resistance of the coil.When the coil is connected to a $DC$ battery of $emf$ $E = 12 \,V$ and internal resistance $r = 4 \,\Omega$,the total resistance of the circuit is $R_{total} = R + r = 4 \,\Omega + 4 \,\Omega = 8 \,\Omega$.The steady-state current $I$ is given by $I = E / R_{total} = 12 / 8 = 1.5 \,A$.

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$A$ series $LCR$ circuit has $L=0.01\,H$,$R=10\,\Omega$,and $C=1\,\mu F$ and it is connected to an $AC$ voltage of amplitude $V_m = 50\,V$. At a frequency $60\%$ lower than the resonant frequency,the amplitude of the current will be approximately $...............\,mA$.

Is the current distribution shown in the figure possible?

Statement-$I$: $A$ capacitor can be used in an $a.c.$ circuit in place of a choke coil.
Statement-$II$: $A$ capacitor blocks $d.c.$ and allows $a.c.$ to pass.

The phase angle between $e.m.f.$ and current in an $LCR$ series $ac$ circuit is:

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