A closed organ pipe of length 1.2 , m vibrate | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a closed organ pipe,the length $L$ is related to the wavelength $\lambda$ for the $n^{th}$ overtone as $L = (2n + 1) \frac{\lambda}{4}$.For th

Vedclass · Accepted Answer

$0.4 \, m$ from the open end

Vedclass · Answer

(B) For a closed organ pipe,the length $L$ is related to the wavelength $\lambda$ for the $n^{th}$ overtone as $L = (2n + 1) \frac{\lambda}{4}$.For the first overtone,$n = 1$,so $L = \frac{3\lambda}{4}$.Given $L = 1.2 \, m$,we have $\frac{3\lambda}{4} = 1.2 \, m$,which gives $\lambda = 1.6 \, m$.In a standing wave,pressure variation is maximum at the displacement nodes.In a closed organ pipe,the open end is a displacement antinode (pressure node),and the closed end is a displacement node (pressure antinode).The displacement nodes occur at distances $x = 0, \frac{\lambda}{2}, \lambda, \dots$ from the closed end.Alternatively,measuring from the open end,the displacement nodes occur at $x = \frac{\lambda}{4}, \frac{3\lambda}{4}, \dots$ from the open end.For the first overtone,the first displacement node (maximum pressure variation) is at $\frac{\lambda}{4} = \frac{1.6}{4} = 0.4 \, m$ from the open end.

$A$ closed organ pipe of length $1.2 \, m$ vibrates in its first overtone mode. The pressure variation is maximum at:

Similar Questions

The first overtone frequency of an open organ pipe is equal to the fundamental frequency of a closed organ pipe. If the length of the closed organ pipe is $20 \, cm$,the length of the open organ pipe is ........ $cm$.

Find the fundamental frequency of a closed pipe,if the length of the air column is $42 \, m$. (speed of sound in air $= 332 \, m/s$) (in $, Hz$)

In the resonance experiment,two air columns (closed at one end) of $100 \ cm$ and $120 \ cm$ long,give $15$ beats per second when each one is sounding in the respective fundamental modes. The velocity of sound in the air column is $:$ (in $m/s$)

$A$ tuning fork of frequency $340 \ Hz$ is vibrated just above a tube of $120 \ cm$ height. Water is poured slowly into the tube. What is the minimum height of water necessary for resonance (in $cm$)? (Speed of sound in air $= 340 \ m/s$)

Two closed pipes have the same fundamental frequency. One is filled with oxygen and the other with hydrogen at the same temperature. The ratio of their lengths respectively is

Vedclass Test Series

Exam Paper Generator

Online Exam Module