$A$ child has a die whose six faces show the letters as given below:
$A$,$B$,$C$,$D$,$E$,$A$
The die is thrown once. What is the probability of getting:
$(i)$ $A$?
(ii) $D$?

(N/A) The total number of possible outcomes on the die is $6$ (since there are $6$ faces).
$(i)$ The number of faces having the letter $A$ is $2$.
Therefore,the probability of getting $A$ is $P(A) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{2}{6} = \frac{1}{3}$.
(ii) The number of faces having the letter $D$ is $1$.
Therefore,the probability of getting $D$ is $P(D) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{1}{6}$.