$A$ box contains $5$ red marbles,$8$ white marbles and $4$ green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be
$(i)$ red?
$(ii)$ white?
$(iii)$ not green?

  • A
    $\frac{5}{17}, \frac{8}{17}, \frac{13}{17}$
  • B
    $\frac{8}{17}, \frac{5}{17}, \frac{13}{17}$
  • C
    $\frac{5}{17}, \frac{4}{17}, \frac{8}{17}$
  • D
    $\frac{13}{17}, \frac{5}{17}, \frac{8}{17}$

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Suppose we throw a die once. $(i)$ What is the probability of getting a number greater than $4$? $(ii)$ What is the probability of getting a number less than or equal to $4$?

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$(i)$ Complete the following table:
$\begin{array}{|l|c|c|c|c|c|c|c|c|c|c|c|} \hline \text{Sum} & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 \\ \hline \text{Prob.} & \frac{1}{36} & & & & & & \frac{5}{36} & & & & \frac{1}{36} \\ \hline \end{array}$
$(ii)$ $A$ student argues that 'there are $11$ possible outcomes $2, 3, 4, 5, 6, 7, 8, 9, 10, 11$ and $12$. Therefore,each of them has a probability $\frac{1}{11}$.' Do you agree with this argument? Justify your answer.

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$A$ jar contains $24$ marbles,some are green and others are blue. If a marble is drawn at random from the jar,the probability that it is green is $\frac{2}{3}$. Find the number of blue balls in the jar.

$A$ box contains $90$ discs which are numbered from $1$ to $90$. If one disc is drawn at random from the box, find the probability that it bears:
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