A charged particle of charge $q$ and mass $m$, gets deflected through an angle $\theta$ upon passing through a square region of side $a$, which contains a uniform magnetic field $B$ normal to its plane. Assuming that the particle entered the square at right angles to one side, what is the speed of the particle?
$\frac{q B}{m} a \cot \theta$
$\frac{q B}{m} a \tan \theta$
$\frac{q B}{m} a \cot ^2 \theta$
$\frac{q B}{m} \alpha \tan ^2 \theta$
If the direction of the initial velocity of the charged particle is neither along nor perpendicular to that of the magnetic field, then the orbit will be
A proton and an $\alpha$ -particle, having kinetic energies $K _{ p }$ and $K _{\alpha},$ respectively, enter into $a$ magnetic field at right angles.
The ratio of the radii of trajectory of proton to that of $\alpha$ -particle is $2: 1 .$ The ratio of $K _{ p }: K _{\alpha}$ is :
Which one of the following options represents the magnetic field $\vec{B}$ at $O$ due to the current flowing in the given wire segments lying on the $x y$ plane?
If cathode rays are projected at right angles to a magnetic field, their trajectory is
An electron is travelling horizontally towards east. A magnetic field in vertically downward direction exerts a force on the electron along