A charge q is placed at the centre of the lin | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Suppose in the following figure. equilibrium of charge $\mathrm{B}$ is considered. Hence for it's

equilibrium $\left|\mathrm{F}_{\mathrm{A}}\ri

Vedclass · Accepted Answer

$ - \frac{Q}{4}$

Vedclass · Answer

Suppose in the following figure. equilibrium of charge $\mathrm{B}$ is considered. Hence for it's

equilibrium $\left|\mathrm{F}_{\mathrm{A}}\right|=\left|\mathrm{F}_{\mathrm{C}}\right|$

$\Rightarrow \frac{1}{4 \pi \varepsilon_{0}} \frac{\mathrm{Q}^{2}}{4 \mathrm{x}^{2}}=\frac{1}{4 \pi \varepsilon_{0}} \frac{\mathrm{qQ}}{\mathrm{x}^{2}} \Rightarrow \mathrm{q}=\frac{-\mathrm{Q}}{4}$

Short Trick : For such type of problem the magnitude of middle charge can be determined if either of the extreme charge is in equilibrium by using the following formula.

In charge $\mathrm{A}$ is in equilibrium then $\mathrm{q}=$ $-Q_{B}\left(\frac{x_{1}}{x}\right)^{2}$

In charge $\mathrm{B}$ is in equilibrium the $\mathrm{q}=-\mathrm{Q}_{\mathrm{A}}\left(\frac{\mathrm{x}_{2}}{\mathrm{x}}\right)^{2}$

If the whole system is in equilibrium then use either of the above formula.

A charge $q$ is placed at the centre of the line joining two equal charges $Q$. The system of the three charges will be in equilibrium, if $q$ is equal to

Similar Questions

In the given figure, three capacitors $C_1, C_2$ and $C_3$ are joined to a battery, with symbols having their usual meanings, the correct conditions will be

A capacitor of capacitance $C_0$ is charged to a potential $V_0$ and is connected with another capacitor of capacitance $C$ as shown. After closing the switch $S$, the common potential across the two capacitors becomes $V$. The capacitance $C$ is given by

Two point charges $+q$ and $-q$ are held fixed at $(-d, 0)$ and $(+d, 0)$ respectively of a $(x, y)$ coordinate system. Then

Charges $+q$ and $-q$ are placed at points $A$ and $B$ respectively which are at distance $2\,L$ apart, $C$ is the midpoint between $A$ and $B$ . The work done in moving a charge $+ Q$ along the semicircle $CRD$ is

A charge $Q$ is divided into two parts of $q$ and $Q - q$. If the coulomb repulsion between them when they are separated is to be maximum, the ratio of $\frac{Q}{q}$ should be