A charge $q$ coulomb moves in a circle at $n$ revolutions per second and the radius of the circle is $r$ metre; then magnetic field at the centre of the circle is
$\frac{{2\pi q}}{{nr}} \times {10^{ - 7}}\frac{N}{{A - m}}$
$\frac{{2\pi q}}{r} \times {10^{ - 7}}\frac{N}{{A - m}}$
$\frac{{2\pi nq}}{r} \times {10^{ - 7}}\frac{N}{{A - m}}$
$\frac{{2\pi q}}{r}\frac{N}{{A - m}}$
A charge particle $A$ of charge $q = 2\,\, C$ has velocity $v = 100\,\, m/s.$ When it passes through point Aand has velocity in the direction shown. The strength of magnetic field at point $B$ due to this moving charge is.......$\mu T$ $(r = 2\,\, m).$
$AB$ and $CD$ are long straight conductor, distance $d$ apart, carrying a current $I$. The magnetic field at the midpoint of $BC$ is
In the figure, what is the magnetic field at the point $O$
A current of $0.1\, A$ circulates around a coil of $100$ $turns$ and having a radius equal to $5\, cm$. The magnetic field set up at the centre of the coil is $({\mu _0} = 4\pi \times {10^{ - 7}}\,weber/ampere - metre)$
Two concentric circular coils of ten turns each are situated in the same plane. Their radii are $20$ and $40\, cm$ and they carry respectively $0.2$ and $0.3$ $ampere$ current in opposite direction. The magnetic field in $weber/{m^2}$ at the centre is