A Carnot engine absorbs an amount Q of heat f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a Carnot engine,the efficiency $\eta$ is given by the ratio of temperatures of the sink $(T_2)$ and the source $(T_1)$:$\eta = 1 - \frac{T_2}{

Vedclass · Accepted Answer

$Q / 3$

Vedclass · Answer

(B) For a Carnot engine,the efficiency $\eta$ is given by the ratio of temperatures of the sink $(T_2)$ and the source $(T_1)$:$\eta = 1 - \frac{T_2}{T_1}$Given,$T_1 = T$ and $T_2 = T/3$.Therefore,$\eta = 1 - \frac{T/3}{T} = 1 - \frac{1}{3} = \frac{2}{3}$.Also,the efficiency is defined as $\eta = 1 - \frac{Q_2}{Q_1}$,where $Q_1$ is the heat absorbed and $Q_2$ is the heat rejected.Equating the two expressions for efficiency:$\frac{2}{3} = 1 - \frac{Q_2}{Q}$$\frac{Q_2}{Q} = 1 - \frac{2}{3} = \frac{1}{3}$$Q_2 = \frac{Q}{3}$.Thus,the amount of heat rejected is $Q/3$.

$A$ Carnot engine absorbs an amount $Q$ of heat from a reservoir at an absolute temperature $T$ and rejects heat to a sink at a temperature of $T/3$. The amount of heat rejected is

Similar Questions

$A$ Carnot heat engine absorbs $600 \ J$ of heat from a source at a temperature of $127^{\circ} C$ and rejects $400 \ J$ of heat to a sink in each cycle. The temperature of the sink is (in $K$)

What is a Carnot engine?

$A$ reversible engine converts one-sixth of the heat supplied into work. When the temperature of the sink is reduced by $62^{\circ} C$,the efficiency of the engine is doubled. The temperatures of the source and sink are

Consider the given series combination of Carnot cycles. If $W_1 = W_2$,then the value of $T$ is ...... $K$ (all temperatures are maintained at their respective values).

What is the common feature of a heat engine based on a cyclic process?

Vedclass Test Series

Exam Paper Generator

Online Exam Module