A card is selected from a pack of $52$ cards. Calculate the probability that the card is an ace
Let $E$ be the event in which the card drawn is an ace.
since there are $4$ ace in a pack of $52$ cards, $n(E)=4$
$\therefore P(E)=\frac{\text { Number of outcomes favourable to } E}{\text { Total mumber of possible outcomes }}=\frac{n(E)}{n(S)}=\frac{4}{52}=\frac{1}{13}$
Two dice are thrown. The events $A, B$ and $C$ are as follows:
$A:$ getting an even number on the first die.
$B:$ getting an odd number on the first die.
$C:$ getting the sum of the numbers on the dice $\leq 5$
Describe the events $B$ and $C$
If $P(A) = 0.65,\,\,P(B) = 0.15,$ then $P(\bar A) + P(\bar B) = $
Two dice are thrown together. If the numbers appearing on the two dice are different, then what is the probability that the sum is $6$
If two dice are thrown simultaneously then probability that $1$ comes on first dice is
Two cards are drawn from a pack of $52$ cards. What is the probability that at least one of the cards drawn is an ace