A card is drawn from a pack of 52 cards. If A | vedclass

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(A) The total number of cards is $n(S) = 52$. Number of diamond cards is $n(A) = 13$,so $P(A) = \frac{13}{52} = \frac{1}{4}$. Number of ace cards is $

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(A) The total number of cards is $n(S) = 52$. Number of diamond cards is $n(A) = 13$,so $P(A) = \frac{13}{52} = \frac{1}{4}$. Number of ace cards is $n(B) = 4$,so $P(B) = \frac{4}{52} = \frac{1}{13}$. The number of ace of diamond cards is $n(A \cap B) = 1$,so $P(A \cap B) = \frac{1}{52}$. Now,check for independence: $P(A) 	imes P(B) = \frac{1}{4} 	imes \frac{1}{13} = \frac{1}{52}$. Since $P(A \cap B) = P(A) 	imes P(B)$,the events $A$ and $B$ are independent.

$A$ card is drawn from a pack of $52$ cards. If $A =$ card is of diamond,$B =$ card is an ace,and $A \cap B =$ card is the ace of diamond,then events $A$ and $B$ are

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