A car travels $6 \,km$ towards north at an angle of $45^o $ to the east and then travels distance of $4 \,km$ towards north at an angle of $135^o $ to the east. How far is the point from the starting point. What angle does the straight line joining its initial and final position makes with the east
$\sqrt {50} \,km$ and ${\tan ^{ - 1}}(5)$
$10 \,km$ and ${\tan ^{ - 1}}(\sqrt 5 )$
$\sqrt {52} \,km$ and ${\tan ^{ - 1}}(5)$
$\sqrt {52} \,km$ and ${\tan ^{ - 1}}(\sqrt 5 )$
A particle moves with constant speed $v$ along a regular hexagon $ABCDEF$ in the same order. Then the magnitude of the average velocity for its motion from $A$ to
The position vector of a particle changes with time according to the relation $\vec r\left( t \right) = 15{t^2}\hat i + \left( {4 - 20{t^2}} \right)\hat j$. What is the magnitude of the acceleration at $t = 1$ ?
If the initial velocity in horizontal direction of a projectile is unit vector $\hat{i}$ and the equation of trajectory is $y =5 x (1- x )$. The $y$ component vector of the initial velocity is.
(Take $g=10\,m / s ^{2}$ )
Motion of a particle in $x - y$ plane is described by a set of following equations $x=4 \sin \left(\frac{\pi}{2}-\omega t\right) m$ and $y=4 \sin (\omega t) m$. The path of particle will be
The displacement $x$ of a particle depend on time $t$ as $x = \alpha {t^{^2}} - \beta {t^3}$