If the initial velocity in horizontal directi | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$u_{x}=1$

$y=5 x(1-x)$

$\frac{d y}{d t}=5 \frac{d x}{d t}-10 x \frac{d x}{d t}$

For initial $y$-component of velocity

$u _{ y }=\left(\fra

Vedclass · Accepted Answer

$5$

Vedclass · Answer

$u_{x}=1$

$y=5 x(1-x)$

$\frac{d y}{d t}=5 \frac{d x}{d t}-10 x \frac{d x}{d t}$

For initial $y$-component of velocity

$u _{ y }=\left(\frac{ dy }{ dt }\right)_{ x =0} \Rightarrow 5(1)=5$

$\overrightarrow{ u }_{ y }=5\,\hat{j }$

If the initial velocity in horizontal direction of a projectile is unit vector $\hat{i}$ and the equation of trajectory is $y =5 x (1- x )$. The $y$ component vector of the initial velocity is.

(Take $g=10\,m / s ^{2}$ )

Similar Questions

What do you mean by projectile motion and projectile particle ? Find the value of the position of a projectile particle at any instant of time.

A body is moving with velocity $30\; m/s$ towards east. After $10$ seconds its velocity becomes $40\; m/s$ towards north. The average acceleration of the body is ...... $m/s^2$

If two forces of equal magnitudes act simultaneously on a body in the east and the north directions then

A particle has initial velocity $\left( {2\hat i + 3\hat j} \right)$ and acceleration $\left( {0.3\hat i + 0.2\hat j} \right)$. The magnitude of velocity after $10\, seconds$ will be

The coordinates of a moving particle at any time $t$ are given by $x = a\, t^2$ and $y = b\, t^2$. The speed of the particle is

If the initial velocity in horizontal direction of a projectile is unit vector $\hat{i}$ and the equation of trajectory is $y =5 x (1- x )$. The $y$ component vector of the initial velocity is. (Take $g=10\,m / s ^{2}$ )