(A) Initial energy stored in capacitor $C_1$ is $U_i = \frac{1}{2} C_1 V_0^2 = \frac{q^2}{2C_1}$,where $q = C_1 V_0$ is the charge on the capacitor.Wh

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(A) Initial energy stored in capacitor $C_1$ is $U_i = \frac{1}{2} C_1 V_0^2 = \frac{q^2}{2C_1}$,where $q = C_1 V_0$ is the charge on the capacitor.When the switch $S$ is closed,the charge $q$ is shared between the two capacitors $C_1$ and $C_2$ connected in parallel. The total capacitance becomes $C_{eq} = C_1 + C_2$.The final energy stored in the system is $U_f = \frac{q^2}{2 C_{eq}} = \frac{q^2}{2(C_1 + C_2)}$.The ratio of the energies is $\frac{U_i}{U_f} = \frac{q^2 / (2C_1)}{q^2 / (2(C_1 + C_2))} = \frac{C_1 + C_2}{C_1}$.

Class 12 Physics Electric Potential and Capacitance Sharing of Charge in Capacitor Circuit

Medium

$A$ capacitor of capacity $C_1$ is charged to a potential of $V_0$. After disconnecting it from the battery,it is connected to a capacitor of capacity $C_2$ as shown in the figure. The ratio of the total energy before and after the connection of switch $S$ is:

A
$(C_1 + C_2) / C_1$
B
$C_1 / (C_1 + C_2)$
C
$C_1 C_2$
D
$C_1 / C_2$

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Class 12

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Electric Potential and Capacitance

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Sharing of Charge in Capacitor Circuit

$A$ capacitor of capacitance $C$ is charged to a potential difference $V_0$. The charging battery is removed and the capacitor is now connected to an uncharged capacitor of unknown capacity. The potential difference across the combination becomes $V$. The unknown capacitance is

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Choose the incorrect statement from the following: When two identical capacitors are charged individually to different potentials and connected in parallel to each other after disconnecting them from the source.

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There are two identical capacitors. The first one is uncharged and filled with a dielectric of constant $K$,while the second one is charged to potential $V$ and has air between its plates. If the two capacitors are joined in parallel,the common potential will be:

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Consider two uncharged capacitors of equal capacitance $200 \text{ pF}$. One of them is charged by a $100 \text{ V}$ supply and disconnected. Now,this capacitor is connected to the uncharged capacitor. The amount of electrostatic energy lost in the process is:

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Two spheres of radii $R_1$ and $R_2$ have the same initial charge $q$. They are connected by a copper wire. After they are disconnected,the potential of each sphere is $V$. What was the initial charge $q$ on each sphere?

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$A$ capacitor of capacity $C_1$ is charged to a potential of $V_0$. After disconnecting it from the battery,it is connected to a capacitor of capacity $C_2$ as shown in the figure. The ratio of the total energy before and after the connection of switch $S$ is:

Similar Questions

$A$ capacitor of capacitance $C$ is charged to a potential difference $V_0$. The charging battery is removed and the capacitor is now connected to an uncharged capacitor of unknown capacity. The potential difference across the combination becomes $V$. The unknown capacitance is

Choose the incorrect statement from the following: When two identical capacitors are charged individually to different potentials and connected in parallel to each other after disconnecting them from the source.

There are two identical capacitors. The first one is uncharged and filled with a dielectric of constant $K$,while the second one is charged to potential $V$ and has air between its plates. If the two capacitors are joined in parallel,the common potential will be:

Consider two uncharged capacitors of equal capacitance $200 \text{ pF}$. One of them is charged by a $100 \text{ V}$ supply and disconnected. Now,this capacitor is connected to the uncharged capacitor. The amount of electrostatic energy lost in the process is:

Two spheres of radii $R_1$ and $R_2$ have the same initial charge $q$. They are connected by a copper wire. After they are disconnected,the potential of each sphere is $V$. What was the initial charge $q$ on each sphere?

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