A capacitor is charged by using a battery which is then disconnected. A dielectric slab is then slipped between the plates, which results in
A capacitor is charged by using a battery which is then disconnected. A dielectric slab is then slipped between the plates, which results in
- A
Reduction of charge on the plates and increase of potential difference across the plates
- B
Increase in the potential difference across the plate, reduction in stored energy, but no change in the charge on the plates
- C
Decrease in the potential difference across the plates, reduction in the stored energy, but no change in the charge on the plates
- D
None of the above
Similar Questions
In one design of capacitor thin sheets ot metal of area $80\ mm \times 80\ mm$ sandwich between them a piece of paper whose thickness is $40\ μm$. The relative permittivity of the paper is $4.0$ and its dielectric strength is $20\ MVm^{-1}$. Calculate the maximum charge that can be put on the capacitor
[permittivity of free space $ = 9 \times 10^{-12}\ Fm^{-1}$]
In one design of capacitor thin sheets ot metal of area $80\ mm \times 80\ mm$ sandwich between them a piece of paper whose thickness is $40\ μm$. The relative permittivity of the paper is $4.0$ and its dielectric strength is $20\ MVm^{-1}$. Calculate the maximum charge that can be put on the capacitor
[permittivity of free space $ = 9 \times 10^{-12}\ Fm^{-1}$]
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