A bullet of mass 40 ,g is fired from a gun of | vedclass

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(B) According to the law of conservation of linear momentum,the total momentum of the system before firing is equal to the total momentum after firing

Vedclass · Accepted Answer

$1.6 \,m/s$ opposite to the direction of the bullet

Vedclass · Answer

(B) According to the law of conservation of linear momentum,the total momentum of the system before firing is equal to the total momentum after firing.Initial momentum $(P_i)$ = $0$ (since both are at rest).Final momentum $(P_f)$ = $m_b v_b + m_g v_g$,where $m_b = 40 \,g = 0.04 \,kg$,$v_b = 400 \,m/s$,$m_g = 10 \,kg$,and $v_g$ is the recoil velocity.$P_i = P_f$$0 = (0.04 \,kg 	imes 400 \,m/s) + (10 \,kg 	imes v_g)$$0 = 16 + 10 v_g$$10 v_g = -16$$v_g = -1.6 \,m/s$.The negative sign indicates that the recoil velocity is in the direction opposite to the motion of the bullet.

$A$ bullet of mass $40 \,g$ is fired from a gun of mass $10 \,kg$. If the velocity of the bullet is $400 \,m/s$,then the recoil velocity of the gun will be ..........

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