A brown ring is formed in the ring test for N | vedclass

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(A) The brown ring test is a common laboratory test for the detection of the nitrate ion $(NO_{3}^{-})$.When freshly prepared iron$(II)$ sulfate solut

Vedclass · Accepted Answer

$[Fe(H_{2}O)_{5}(NO)]^{2+}$

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(A) The brown ring test is a common laboratory test for the detection of the nitrate ion $(NO_{3}^{-})$.When freshly prepared iron$(II)$ sulfate solution is added to a solution containing nitrate ions,followed by the slow addition of concentrated sulfuric acid along the sides of the test tube,a brown ring forms at the interface of the two layers.The reaction involves the reduction of nitrate to nitric oxide $(NO)$,which then reacts with the hexaaquairon$(II)$ complex to form the brown-colored nitrosyl complex,$[Fe(H_{2}O)_{5}(NO)]^{2+}$.The chemical equations are:$NO_{3}^{-} + 3Fe^{2+} + 4H^{+} \rightarrow 3Fe^{3+} + NO + 2H_{2}O$$[Fe(H_{2}O)_{6}]^{2+} + NO \rightarrow [Fe(H_{2}O)_{5}(NO)]^{2+} + H_{2}O$

$A$ brown ring is formed in the ring test for $NO_{3}^{-}$ ion. It is due to the formation of :-

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