A bomb is projected with 200 , m/s at an angl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Initial velocity of the bomb is $u = 200 \, m/s$ at $	heta = 60^o$. The horizontal component of velocity at the highest point is $v_x = u \cos(60

Vedclass · Accepted Answer

$300 \, m/s$ in the horizontal direction

Vedclass · Answer

(D) Initial velocity of the bomb is $u = 200 \, m/s$ at $	heta = 60^o$. The horizontal component of velocity at the highest point is $v_x = u \cos(60^o) = 200 	imes 0.5 = 100 \, m/s$. At the highest point,the vertical component of velocity is $0$. Let the mass of the bomb be $3m$. After the explosion,the three particles each have mass $m$. By the Law of Conservation of Linear Momentum in the horizontal direction: $(3m)v_x = m(v_{1x}) + m(v_{2x}) + m(v_{3x})$. Since the first and second particles move vertically,their horizontal velocity components are $v_{1x} = 0$ and $v_{2x} = 0$. Thus,$(3m)(100) = m(0) + m(0) + m(v_{3x})$. $300m = m(v_{3x}) \implies v_{3x} = 300 \, m/s$. By the Law of Conservation of Linear Momentum in the vertical direction: $(3m)(0) = m(v_{1y}) + m(v_{2y}) + m(v_{3y})$. Given $v_{1y} = 100 \, m/s$ and $v_{2y} = -100 \, m/s$. $0 = m(100) + m(-100) + m(v_{3y}) \implies v_{3y} = 0$. Therefore,the third particle moves with a velocity of $300 \, m/s$ in the horizontal direction.

Similar Questions

If $f(x) = \begin{cases} \frac{x-1}{2x^2-7x+5}, & \text{for } x \neq 1 \\ -\frac{1}{3}, & \text{for } x=1 \end{cases}$,then $f'(1)$ is equal to:

$\frac{(1+i)^{2011}}{(1-i)^{2009}}$ is equal to

The main objective of the production/use of herbicide-resistant $GM$ crops is to

$A$ coil of $n$ turns and resistance $R \ \Omega$ is connected in series with a resistance $R/2$. The combination is moved for time $t$ seconds through a magnetic flux change from $\phi_{1}$ to $\phi_{2}$. The induced current in the circuit is:

$CsBr$ has $b.c.c.$ structure with edge length $4.3 \ \mathring{A}$. The shortest inter-ionic distance between $Cs^{+}$ and $Br^{-}$ is .............. $\mathring{A}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module