A body of mass m is moving in a circle of rad | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The work done $W$ by a force $\vec{F}$ is given by the dot product $W = \int \vec{F} \cdot d\vec{s}$.In uniform circular motion,the centripetal fo

Vedclass · Accepted Answer

Zero

Vedclass · Answer

(B) The work done $W$ by a force $\vec{F}$ is given by the dot product $W = \int \vec{F} \cdot d\vec{s}$.In uniform circular motion,the centripetal force $\vec{F}$ is always directed towards the centre of the circle.The displacement vector $d\vec{s}$ at any point on the circular path is always tangent to the circle.Since the radius (and thus the force) is always perpendicular to the tangent (displacement),the angle $	heta$ between the force $\vec{F}$ and the displacement $d\vec{s}$ is always $90^\circ$.Therefore,the work done $W = \int F \cdot ds \cdot \cos(90^\circ) = \int F \cdot ds \cdot 0 = 0$.Thus,the work done by the centripetal force in moving the body over any distance along the circular path is zero.

$A$ body of mass $m$ is moving in a circle of radius $r$ with a constant speed $v$. The force on the body is $\frac{mv^2}{r}$ and is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle?

Similar Questions

Which one of the following elements in plants is not remobilised?

The modern man differs from the apes in

Which of the following is not a peroxo acid?

$\sinh^{-1}(2^{3/2})$ is equal to :

Vedclass Test Series

Exam Paper Generator

Online Exam Module