$A$ body of mass $m_1$ is moving with a velocity $V$. It collides with another stationary body of mass $m_2$. They get embedded. At the point of collision,the velocity of the system

Two bodies of the same mass $m$ are moving with the same speed $v_0$,but in different directions in a plane. They undergo a completely inelastic collision and move together thereafter with a final speed which is half of their initial speed. The angle between the initial velocities of the two bodies (in degrees) is:

Statement $1$: In a perfectly inelastic collision,the total energy of two particles moving in the same direction is not completely lost.
Statement $2$: The principle of conservation of momentum is valid for all types of collisions.

$A$ particle of mass $m$ moving with velocity $v$ collides with a stationary particle of mass $2m$ and sticks to it. What will be the speed of the system?

$A$ body of mass $m$ is moving with velocity $u$ as shown in the figure and it collides with a body of mass $4m$ at rest. If the collision is perfectly inelastic,then the percentage loss in kinetic energy is:

$A$ body of mass $m$ moving with velocity $v$ collides head-on with another body of mass $2m$ which is initially at rest. If the collision is perfectly inelastic,what is the loss in kinetic energy of the system?