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(B) Let the two bodies have mass $m$ and initial speed $v_0$. Let the angle between their initial velocity vectors be $2	heta$. By symmetry,the combi

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$120$

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(B) Let the two bodies have mass $m$ and initial speed $v_0$. Let the angle between their initial velocity vectors be $2	heta$. By symmetry,the combined mass $2m$ will move along the angle bisector of the initial velocity vectors with a final speed $v_f = v_0/2$. Applying the law of conservation of linear momentum along the direction of the final velocity:$m v_0 \cos 	heta + m v_0 \cos 	heta = (2m) v_f$$2 m v_0 \cos 	heta = 2 m (v_0/2)$$2 m v_0 \cos 	heta = m v_0$$\cos 	heta = 1/2$$	heta = 60^\circ$The angle between the initial velocities is $2	heta = 2 	imes 60^\circ = 120^\circ$.

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