A body of mass 3, kg hits a wall at an angle | vedclass

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Question

$\begin{array}{l}
Change\,in\,momentum\,along\,the\,wall\
 = mv\cos {60^ \circ } - mv\cos {60^ \circ } = 0\
Change\,in\,momentum\,perpendicu

Vedclass · Accepted Answer

$150\sqrt 3 \,N$

Vedclass · Answer

$\begin{array}{l}
Change\,in\,momentum\,along\,the\,wall\
 = mv\cos {60^ \circ } - mv\cos {60^ \circ } = 0\
Change\,in\,momentum\,perpendicular\,\
to\,the\,wall\
 = mv\sin {60^ \circ } - \left( { - mv\sin {{60}^ \circ }} ight)\
 = 2mv\,\sin {60^ \circ }\
	herefore Applied\,force
\end{array}$

$\begin{array}{l}
 = \frac{{Change\,in\,momentum}}{{Time}}\
 = \frac{{2\,mv\sin {{60}^ \circ }}}{{0.20}}\
 = \frac{{2 	imes 3 	imes 10 	imes \sqrt 3 }}{{2 	imes 0.20}} = 50 	imes 3\sqrt 3 \
 = 150\sqrt 3 \,newton
\end{array}$

A body of mass $3\, kg$ hits a wall at an angle of $60^o$ and returns at the same angle. The impact time was $0.2 \;.s$ Calculate the force exerted on the wall

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