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(B) Given:Mass of the body,$m = 5 \, kg$Initial velocity,$u = 20 \, m/s$Force applied,$F = 100 \, N$Time duration,$t = 10 \, s$According to Newton's s

Vedclass · Accepted Answer

$220$

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(B) Given:Mass of the body,$m = 5 \, kg$Initial velocity,$u = 20 \, m/s$Force applied,$F = 100 \, N$Time duration,$t = 10 \, s$According to Newton's second law of motion,the acceleration $a$ is given by $a = \frac{F}{m} = \frac{100}{5} = 20 \, m/s^2$.Using the first equation of motion,$v = u + at$,we get:$v = 20 + (20 	imes 10)$$v = 20 + 200 = 220 \, m/s$.Therefore,the final velocity of the body is $220 \, m/s$.

$A$ body of $5 \, kg$ is moving with a velocity of $20 \, m/s$. If a force of $100 \, N$ is applied on it for $10 \, s$ in the same direction as its velocity,what will be the final velocity of the body in $m/s$?

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