$A$ body is thrown vertically up from the ground. It reaches a maximum height of $100\,m$ in $5\,sec$. After what time will it reach the ground from the maximum height position?

$A$ ball thrown vertically upwards reaches a height of $25 \,m$ in $1 \,s$. The ratio of the total distance covered by the ball in time $t=2 \,s$ and $t=4 \,s$ is (Use $g=10 \,m/s^2$)

$A$ balloon was moving upwards with a uniform velocity of $10 \, m/s$. An object of finite mass is dropped from the balloon when it was at a height of $75 \, m$ from the ground level. The height of the balloon from the ground when the object strikes the ground was around (in $m$). (Take the value of $g$ as $10 \, m/s^2$)

$A$ body thrown vertically upwards with an initial speed of $96\,ft/\sec$ reaches the ground after..........$sec$ $(g = 32\,ft/\sec^2)$.

$A$ tennis ball is released from a height $h$ and after freely falling on a wooden floor,it rebounds and reaches a height $\frac{h}{2}$. The velocity versus height of the ball during its motion may be represented graphically by (graphs are drawn schematically and not to scale):

$A$ ball is thrown up vertically with a certain velocity so that it reaches a maximum height $h$. Find the ratio of the times at which it is at height $\frac{h}{3}$ while going up and coming down respectively.