A body is initially at rest. It undergoes one | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the mass of the body be $m$ and the constant acceleration be $a$.According to Newton's second law of motion,the force $F$ acting on the body i

Vedclass · Accepted Answer

$t$

Vedclass · Answer

(B) Let the mass of the body be $m$ and the constant acceleration be $a$.According to Newton's second law of motion,the force $F$ acting on the body is:$F = ma$Since $m$ and $a$ are constants,the force $F$ is also constant.For a body starting from rest $(u = 0)$,the velocity $v$ at time $t$ is given by the equation of motion:$v = u + at = 0 + at = at$Thus,$v \propto t$.Power $P$ delivered to the body is defined as the product of force and velocity:$P = F \cdot v$Substituting the expressions for $F$ and $v$:$P = (ma) \cdot (at) = (ma^2)t$Since $m$ and $a$ are constants,$ma^2$ is also a constant.Therefore,$P \propto t$.

$A$ body is initially at rest. It undergoes one-dimensional motion with constant acceleration. The power delivered to it at time $t$ is proportional to

Similar Questions

$A$ metal crystallises in a face-centred cubic $(FCC)$ structure. If the edge length of its unit cell is $a$,the closest approach between two atoms in the metallic crystal will be:

Which two orbitals are located along the axis and not between the axis?

Two identical thin bar magnets,each of length $l$ and pole strength $m$,are placed at a right angle to each other with the north pole of one touching the south pole of the other. The magnetic moment of the system is:

$A$ disc and a ring of the same mass are rolling. If their kinetic energies are equal,then the ratio of their velocities will be

Hydrolysis of sucrose with dilute aqueous sulphuric acid yields

Vedclass Test Series

Exam Paper Generator

Online Exam Module