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(B) In $S.H.M.$,the potential energy is given by $U = \frac{1}{2} k x^2$ and kinetic energy is given by $K = \frac{1}{2} k (A^2 - x^2)$.At the mean po

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$K.E.$ is maximum when $x = 0$

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(B) In $S.H.M.$,the potential energy is given by $U = \frac{1}{2} k x^2$ and kinetic energy is given by $K = \frac{1}{2} k (A^2 - x^2)$.At the mean position,$x = 0$. Substituting this into the expressions:$U = \frac{1}{2} k (0)^2 = 0$ (Minimum potential energy).$K = \frac{1}{2} k (A^2 - 0^2) = \frac{1}{2} k A^2$ (Maximum kinetic energy).The total energy $E = U + K = \frac{1}{2} k A^2$,which remains constant throughout the motion.Therefore,the kinetic energy is maximum at the mean position $(x = 0)$.

$A$ body executes simple harmonic motion. The potential energy $(P.E.)$,the kinetic energy $(K.E.)$ and total energy $(T.E.)$ are measured as a function of displacement $x$. Which of the following statements is true?

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