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(B) The maximum height $H$ reached by a body projected vertically upwards with an initial velocity $u$ is given by the formula $H = \frac{u^2}{2g}$,wh

Vedclass · Accepted Answer

$200$

Vedclass · Answer

(B) The maximum height $H$ reached by a body projected vertically upwards with an initial velocity $u$ is given by the formula $H = \frac{u^2}{2g}$,where $g$ is the acceleration due to gravity.From this relation,we can see that $H \propto u^2$.For the first body,$H_1 = 50 \ m$ with initial velocity $u_1 = u$.For the second body,the initial velocity $u_2 = 2u$.The mass of the body does not affect the maximum height reached in the absence of air resistance.Therefore,the new maximum height $H_2$ is given by $H_2 = \frac{(2u)^2}{2g} = 4 	imes \frac{u^2}{2g} = 4 	imes H_1$.Substituting the value of $H_1$,we get $H_2 = 4 	imes 50 \ m = 200 \ m$.

$A$ body,thrown upwards with some velocity,reaches a maximum height of $50 \ m$. Another body with double the mass thrown up with double the initial velocity will reach a maximum height of $.......... \ m$.

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