A blue colouration is not obtained when

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(b) $CuS{O_4} + {K_4}[Fe{(CN)_6}] 	o $ no reaction

$4N{H_4}OH + CuS{O_4} 	o \mathop {[Cu{{(N{H_3})}_4}]}\limits_{{m{Deep}}\,{m{blue}}} \,S{O_

Vedclass · Accepted Answer

Copper sulphate solution reacts with ${K_4}[Fe{(CN)_6}]$

Vedclass · Answer

(b) $CuS{O_4} + {K_4}[Fe{(CN)_6}] 	o $ no reaction

$4N{H_4}OH + CuS{O_4} 	o \mathop {[Cu{{(N{H_3})}_4}]}\limits_{{m{Deep}}\,{m{blue}}} \,S{O_4} + 4{H_2}O$

$\mathop {CuS{O_4}}\limits_{{m{Anhydrous}}} + 5{H_2}O 	o \mathop {CuS{O_4}}\limits_{{m{Blue}}} .5{H_2}O$

$4FeC{{l}_{3}}+3N{{a}_{4}}[Fe{{(CN)}_{6}}]	o \underset{\begin{smallmatrix} 
 	ext{Ferric}\,	ext{ferrocyanide} \ 
 \,\,\,\,\,	ext{(Prussian}\,	ext{blue)} 
\end{smallmatrix}}{\mathop{F{{e}_{4}}[Fe{{(CN)}_{6}}]}}\,+12NaCl$

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