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(C) For the block to be held in equilibrium against the wall,the vertical forces must balance,and the horizontal forces must balance.$1$. Vertical equ

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Greater than $W$

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(C) For the block to be held in equilibrium against the wall,the vertical forces must balance,and the horizontal forces must balance.$1$. Vertical equilibrium: The frictional force $f$ acting upwards must balance the weight $W$ of the block acting downwards.$f = W$$2$. Horizontal equilibrium: The applied horizontal force $F$ must be balanced by the normal reaction $R$ from the wall.$R = F$$3$. Friction condition: The maximum static frictional force is given by $f_{max} = \mu R$,where $\mu$ is the coefficient of static friction. To hold the block,we need $f \leq \mu R$.Substituting the values from steps $1$ and $2$:$W \leq \mu F$$F \geq \frac{W}{\mu}$Since the coefficient of static friction $\mu$ for most surfaces is less than $1$ $(\mu  W$.Therefore,the minimum force required is $F = \frac{W}{\mu}$,which is greater than $W$.

$A$ block of weight $W$ is held against a vertical wall by applying a horizontal force $F$. The minimum value of $F$ needed to hold the block is

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