A block of mass m is stationary on a rough pl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In the frame of the inclined plane,the block experiences a pseudo force $ma$ downwards. The effective acceleration due to gravity is $(g+a)$ downw

Vedclass · Accepted Answer

resultant of $m(g+a) \cos 	heta$ normal to the plane and $\mu m(g+a) \cos 	heta$ along the plane

Vedclass · Answer

(D) In the frame of the inclined plane,the block experiences a pseudo force $ma$ downwards. The effective acceleration due to gravity is $(g+a)$ downwards.Resolving the effective weight $m(g+a)$ into components perpendicular and parallel to the inclined plane:$1$. The component perpendicular to the plane is $N = m(g+a) \cos 	heta$. This is the normal force exerted by the plane on the block.$2$. The component parallel to the plane is $m(g+a) \sin 	heta$. This component is balanced by the static friction force $f = \mu N = \mu m(g+a) \cos 	heta$.The total force exerted by the plane on the block is the vector sum (resultant) of the normal force $N$ and the friction force $f$.Therefore,the force is the resultant of $m(g+a) \cos 	heta$ normal to the plane and $\mu m(g+a) \cos 	heta$ along the plane.

Similar Questions

$A$ body is moving up an inclined plane of angle $\theta$ with an initial kinetic energy $E$. The coefficient of friction between the plane and the body is $\mu$. The work done against friction before the body comes to rest is

$A$ block of mass $m$ is at rest with respect to a lift when placed on an inclined plane of inclination $\theta$ inside the lift. If the lift moves upward at a constant velocity $v$,then the work done by the friction force on the block in time $t$ is:

When a body is placed on a rough plane inclined at an angle $\theta$ to the horizontal,its acceleration is

$A$ body of mass $2 \ kg$ slides down with an acceleration of $4 \ m/s^2$ on an inclined plane having a slope of $30^{\circ}$. The external force required to take the same body up the plane with the same acceleration will be (Acceleration due to gravity $= 10 \ m/s^2$) (in $N$)

$A$ body takes just twice the time to slide down a plane inclined at $30^\circ$ to the horizontal as it would if the plane were frictionless. The coefficient of friction between the body and the plane is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module