A block of 200 text{ g} mass moves with a uni | vedclass

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(D) Given: Mass $m = 200 	ext{ g} = 0.2 	ext{ kg}$,Radius $r = 20 	ext{ cm} = 0.2 	ext{ m}$,Time period $T = 40 	ext{ s}$.First,calculate the ang

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$9.859 	imes 10^{-4} 	ext{ N}$

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(D) Given: Mass $m = 200 	ext{ g} = 0.2 	ext{ kg}$,Radius $r = 20 	ext{ cm} = 0.2 	ext{ m}$,Time period $T = 40 	ext{ s}$.First,calculate the angular velocity $\omega = \frac{2\pi}{T} = \frac{2\pi}{40} = \frac{\pi}{20} 	ext{ rad/s}$.The centripetal force required for circular motion is provided by the normal force $N$ exerted by the side walls.$N = F_c = m r \omega^2$.Substituting the values: $N = 0.2 	imes 0.2 	imes (\frac{\pi}{20})^2$.$N = 0.04 	imes \frac{\pi^2}{400} = 0.04 	imes \frac{9.8696}{400} = 0.0001 	imes 9.8696 = 9.8696 	imes 10^{-4} 	ext{ N}$.Rounding to the nearest provided option,the value is approximately $9.859 	imes 10^{-4} 	ext{ N}$.

$A$ block of $200 \text{ g}$ mass moves with a uniform speed in a horizontal circular groove with vertical side walls of radius $20 \text{ cm}$. If the block takes $40 \text{ s}$ to complete one round,the normal force exerted by the side walls of the groove is:

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