A beam of fast-moving alpha particles was dir | vedclass

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(B) According to the Rutherford alpha-particle scattering experiment,most of the space inside an atom is empty,which is why most alpha particles pass

Vedclass · Accepted Answer

$A'$ will be maximum and in $B'$ minimum

Vedclass · Answer

(B) According to the Rutherford alpha-particle scattering experiment,most of the space inside an atom is empty,which is why most alpha particles pass through undeflected (as seen in path $A$ to $A'$). Some alpha particles pass close to the nucleus and undergo small-angle scattering (as seen in path $C$ to $C'$). $A$ very small fraction of alpha particles head directly towards the nucleus and are scattered back at large angles (as seen in path $B$ to $B'$). Therefore,the number of alpha particles passing through the empty space $(A')$ is maximum,while the number of particles scattered back by the nucleus $(B')$ is minimum.

$A$ beam of fast-moving alpha particles was directed towards a thin gold foil. The parts $A'$,$B'$,and $C'$ of the transmitted and reflected beams corresponding to the incident parts $A$,$B$,and $C$ of the beam are shown in the adjoining diagram. The number of alpha particles in:

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$A$ beam of fast-moving alpha particles was directed towards a thin gold foil. The parts $A, B$,and $C$ of the incident beam and their corresponding transmitted or reflected parts $A^{\prime}, B^{\prime}$,and $C^{\prime}$ are shown in the adjoining diagram. The number of alpha particles in:

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In the Rutherford experiment,$\alpha -$ particles are scattered from a nucleus as shown. Out of the four paths,which path is not possible?

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